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Re: HOWTO: Understand Binary and Subnetting
by Jason on Monday June 17, @05:06PM
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Yes, six of them in your example. Here are the six network numbers you get from a class-c subnet mask of 255.255.255.224. The first three octets are arbitrary and could be any valid class-c address.
192.168.1.32
192.168.1.64
192.168.1.96
192.168.1.128
192.168.1.160
192.168.1.192
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Re: HOWTO: Understand Binary and Subnetting
by sib on Tuesday March 18, @02:19PM
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so this means that for class A I srart with 8 and class b with 16 i see here that for a class c address u started off by 32
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Re: HOWTO: Understand Binary and Subnetting
by gene on Tuesday October 04, @06:06PM
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I'm just learning this stuff but I believe you have created 6 subnetworks with 30 usable addresses apiece:33-62,65-94,97-126,129-148,151-180,183-213.This gives you 180 usable numbers instead of the 254 not subnetting would give you.
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